4x^2+73x+265=0

Solution for 4x^2+73x+265=0 equation:

4x^2+73x+265=0

a = 4; b = 73; c = +265;
Δ = b2-4ac
Δ = 732-4·4·265
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-33}{2*4}=\frac{-106}{8}
=-13+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+33}{2*4}=\frac{-40}{8}
=-5
$